Q:

Which of the following gives an equation of a line that passes through the point (,-19) and isparallel to the line that passes through the origin and point (-2, -12)?

Accepted Solution

A:
Answer:[tex]\displaystyle 6x - y = -15, -6x + y = 15, or\:y = 6x + 15[/tex]Step-by-step explanation:First, find the rate of change [slope]:[tex]\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{0 - 12}{0 - 2} = \frac{-12}{-2} = 6[/tex]Then plug [βˆ’1, 9] into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much more swiftly:9 = 6[βˆ’1] + b βˆ’6[tex]\displaystyle 15 = b \\ \\ y = 6x + 15[/tex]If you want it in Standard Form: y = 6x + 15- 6x - 6x__________[tex]\displaystyle -6x + y = 15\:OR\:6x - y = -15[/tex]I am joyous to assist you anytime.