Brooke found the equation of the line passing through the points (–7, 25) and (–4, 13) in slope-intercept form as follows. Question: What was Brooke’s error?•She found the incorrect slope in step 1.•She mixed up the x- and y-coordinates when she plugged in the point in step 2.•She found the incorrect y-intercept in step 2.•She mixed up the slope and y-intercept when she wrote the equation in step 3.

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:[tex]y = mx + b[/tex]Where:m: It's the slopeb: It is the cut-off point with the y axis[tex]m = \frac {y2-y1} {x2-x1}[/tex]We have the following points:[tex](x1, y1): (- 7,25)\\(x2, y2): (- 4,13)[/tex]Substituting the values:[tex]m = \frac {13-25} {- 4 - (- 7)} = \frac {-12} {- 4 + 7} = \frac {-12} {3} = - 4[/tex]Thus, the line is of the form:[tex]y = -4x + b[/tex]We substitute one of the points and find "b":[tex]13 = -4 (-4) + b\\13 = 16 + b\\b = 13-16 = -3[/tex]Finally we have to:[tex]y = -4x-3[/tex]Answer:The equation es [tex]y = -4x-3[/tex]